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Chapter 4

Factorisation — Assertion-Reason Type Questions

Class - 9 ML Aggarwal Understanding ICSE Mathematics



Assertion Reason Type Questions

Question 1

Assertion (A): For the trinomial 2x2 + 8x - 9 cannot be factorised.

Reason (R): For trinomial ax2 + bx + c to be factorised, b2 - 4ac must be a perfect square.

  1. Assertion (A) is true, Reason (R) is false.

  2. Assertion (A) is false, Reason (R) is true.

  3. Both Assertion (A) and Reason (R) are true, and Reason (R) is the correct reason for Assertion (A).

  4. Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct reason (or explanation) for Assertion (A).

Answer

For trinomial ax2 + bx + c to be factorised, the roots are given by the quadratic equation: x = b±b24ac2a\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

For the trinomial ax2 + bx + c to be factorizable into linear factors with rational coefficients, its roots must be rational numbers. This occurs if and only if the expression the discriminant b2 - 4ac, is a perfect square.

∴ Reason (R) is true.

For the trinomial 2x2 + 8x - 9, a = 2, b = 8 and c = -9.

D = b2 - 4ac

= 82 - 4 × 2 × -9

= 64 + 72

= 136.

Since, 136 is not a perfect square. So, 2x2 + 8x - 9 cannot be factorised.

∴ Assertion (A) is true.

∴ Both Assertion (A) and Reason (R) are true, and Reason (R) is the correct reason for Assertion (A).

Hence, option 3 is the correct option.

Question 2

Assertion (A): Factorisation of 4x2 + 9y2 is (2x - 3y)(2x + 3y).

Reason (R): a2 - b2 = (a - b)(a + b)

  1. Assertion (A) is true, Reason (R) is false.

  2. Assertion (A) is false, Reason (R) is true.

  3. Both Assertion (A) and Reason (R) are true, and Reason (R) is the correct reason for Assertion (A).

  4. Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct reason (or explanation) for Assertion (A).

Answer

According to reason: a2 - b2 = (a - b)(a + b)

Expanding, (a - b)(a + b)

⇒ a(a + b) - b(a + b)

⇒ a2 + ab - ab - b2

⇒ a2 - b2.

Thus, (a - b)(a + b) = a2 - b2

∴ Reason (R) is true.

Given,

⇒ (2x - 3y)(2x + 3y)

⇒ 2x(2x + 3y) - 3y(2x + 3y)

⇒ (2x)2 + 6xy - 6xy - (3y)2

⇒ 4x2 - 9y2.

∴ Assertion (A) is false.

∴ Assertion (A) is false, Reason (R) is true.

Hence, option 2 is the correct option.

Question 3

Assertion (A): Factorisation of x3 - 27 is (x - 3)(x2 + 3x + 9).

Reason (R): a3 - b3 = (a - b)(a2 + ab + b2).

  1. Assertion (A) is true, Reason (R) is false.

  2. Assertion (A) is false, Reason (R) is true.

  3. Both Assertion (A) and Reason (R) are true, and Reason (R) is the correct reason for Assertion (A).

  4. Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct reason (or explanation) for Assertion (A).

Answer

We know that,

a3 - b3 = (a - b)(a2 + ab + b2)

∴ Reason (R) is true.

Given,

⇒ x3 - 27

⇒ x3 - 33

⇒ (x - 3)(x2 + 3x + 32)

⇒ (x - 3)(x2 + 3x + 9).

∴ Assertion (A) is true.

∴ Both Assertion (A) and Reason (R) are true, and Reason (R) is the correct reason for Assertion (A).

Hence, option 3 is the correct option.

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