Frequency Distribution — Assertion-Reason Type Questions

Assertion (A) : Classes of the form : 1-10, 11-20, 21-30 etc. are said to be in inclusive form.

Reason (R) : A frequency distribution in which each upper limit as well as lower limit is included is called an inclusive form.

1. A is true, R is false

2. A is false, R is true

3. Both A and R are true

4. Both A and R are false

Answer

Given class intervals 1-10, 11-20, 21-30 etc shows that gap between the upper limit of one class (10) and the lower limit of the next (11).

Since gap shows that these classes don't overlap, thus they are in inclusive form.

∴ Assertion (A) is true.

We know that,

A frequency distribution in which each upper limit as well as lower limit is included is known as inclusive form.

∴ Reason (R) is true.

Both Assertion and Reason are True.

Hence, option 3 is the correct option.

Assertion (A) : In the exclusive form, the upper and lower limits of a class are respectively known as the true upper limit and true lower limit.

Reason (R) : Class size = $\dfrac{\text{ True lower limit} + \text{ True upper limit}}{2}$

1. A is true, R is false

2. A is false, R is true

3. Both A and R are true

4. Both A and R are false

Answer

In the exclusive form (e.g., 10 - 20, 20 - 3)there are no gaps between the classes. Because the classes are continuous, therefore, these limits are indeed the true lower limit and true upper limit.

∴ Assertion (A) is true.

We know that,

Class size = Upper limit - Lower limit

∴ Reason (R) is false.

Hence, option 1 is the correct option.