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Chapter 16

Mean & Median of Ungrouped Data & Frequency Polygon — Exercise 16(C)

Class - 9 RS Aggarwal Mathematics Solutions



Exercise 16C

Question 1

The following table shows the marks obtained by the students of a class in an examination.

MarksNo. of students
0 - 1015
10 - 2032
20 - 3055
30 - 4035
40 - 5013

Draw a frequency polygon.

Answer

Frequency distribution table :

MarksClass markNumber of students (Frequency)
0 - 10515
10 - 201532
20 - 302555
30 - 403535
40 - 504513

Steps to draw frequency polygon :

  1. Take 2 cm along x-axis = 10 marks.

  2. Take 2 cm along y-axis = 10 students.

  3. Find the mid-point of class intervals.

  4. Find points corresponding to given frequencies of classes and the mid-points of class-intervals, and plot them.

  5. Join consecutive points by line segments.

  6. Join first end point with mid-point of class (-10) - 0 with zero frequency and join the other end with mid-point of class 50 - 60 with zero frequency.

The required frequency polygon is shown below:

Join first end point with mid-point of class (-10) - 0 with zero frequency and join the other end with mid-point of class 50 - 60 with zero frequency. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Question 2

Draw a frequency polygon to represent the following data:

Class-intervalFrequency
0 - 99
9 - 1815
18 - 276
27 - 3612
36 - 4518

Answer

Frequency distribution table :

Class - intervalClass markFrequency
0 - 94.59
9 - 1813.515
18 - 2722.56
27 - 3631.512
36 - 4540.518

Steps to draw frequency polygon :

  1. Take 2 cm along x-axis = 9 units.

  2. Take 2 cm along y-axis = 5 units.

  3. Find the mid-point of class intervals.

  4. Find points corresponding to given frequencies of classes and the mid-points of class-intervals, and plot them.

  5. Join consecutive points by line segments.

  6. Join first end point with mid-point of class (-9) - 0 with zero frequency and join the other end with mid-point of class 45 - 54 with zero frequency.

The required frequency polygon is shown below:

Join first end point with mid-point of class (-9) - 0 with zero frequency and join the other end with mid-point of class 45 - 54 with zero frequency. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Question 3

The heights of boys in a school are given below :

Height (in cm)Number of boys
140 - 14524
145 - 15032
150 - 15516
155 - 16020
160 - 16544

Draw a frequency polygon to represent the above data.

Answer

Frequency distribution table :

Height (in cm)Class markFrequency
140 - 145142.524
145 - 150147.532
150 - 155152.516
155 - 160157.520
160 - 165162.544

Steps to draw frequency polygon :

  1. Take 2 cm along x-axis = 5 cm.

  2. Take 2 cm along y-axis = 10 boys.

  3. Find the mid-point of class intervals.

  4. A kink is drawn near x-axis to show that the scale begins at 140.

  5. Find points corresponding to given frequencies of classes and the mid-points of class-intervals, and plot them.

  6. Join consecutive points by line segments.

  7. Join first end point with mid-point of class 135 - 140 with zero frequency and join the other end with mid-point of class 165 - 170 with zero frequency.

The required frequency polygon is shown below :

Join first end point with mid-point of class 135 - 140 with zero frequency and join the other end with mid-point of class 165 - 170 with zero frequency. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Question 4

Draw a frequency polygon to represent the following data :

Weight (in kg)No. of workers
35 - 406
40 - 4517
45 - 5030
50 - 558
55 - 603

Answer

Frequency distribution table :

Weight (in kg)Class markFrequency
35 - 4037.56
40 - 4542.517
45 - 5047.530
50 - 5552.58
55 - 6057.53

Steps to draw frequency polygon :

  1. Take 2 cm along x-axis = 5 kg.

  2. Take 2 cm along y-axis = 5 workers.

  3. Find the mid-point of class intervals.

  4. A kink is drawn near x-axis to show that the scale begins at 35.

  5. Find points corresponding to given frequencies of classes and the mid-points of class-intervals, and plot them.

  6. Join consecutive points by line segments.

  7. Join first end point with mid-point of class 30 - 35 with zero frequency and join the other end with mid-point of class 60 - 65 with zero frequency.

The required frequency polygon is shown below :

Join first end point with mid-point of class 30 - 35 with zero frequency and join the other end with mid-point of class 60 - 65 with zero frequency. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Question 5

Draw a frequency polygon to represent the following data:

Weekly wages (in ₹)No. of workers
750 - 85052
850 - 95041
950 - 105065
1050 - 115054
1150 - 125038

Answer

Frequency distribution table :

Weekly wages (in ₹)Class markFrequency
750 - 85080052
850 - 95090041
950 - 1050100065
1050 - 1150110054
1150 - 1250120038

Steps to draw frequency polygon :

  1. Take 2 cm along x-axis = ₹ 100.

  2. Take 1 cm along y-axis = 5 workers.

  3. Find the mid-point of class intervals.

  4. A kink is drawn near x-axis to show that the scale begins at 750.

  5. Find points corresponding to given frequencies of classes and the mid-points of class-intervals, and plot them.

  6. Join consecutive points by line segments.

  7. Join first end point with mid-point of class 650 - 750 with zero frequency and join the other end with mid-point of class 1250 - 1350 with zero frequency.

The required frequency polygon is shown below:

Join first end point with mid-point of class 650 - 750 with zero frequency and join the other end with mid-point of class 1250 - 1350 with zero frequency. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Question 6

Construct a frequency polygon from the following data :

Class-intervalFrequency
1 - 55
6 - 108
11 - 1512
16 - 207
21 - 254

Answer

The following frequency distribution table is discontinuous. Convert it into continuous frequency distribution.

Adjustment factor = Lower limit of one class - Upper limit of previous class2\dfrac{\text{Lower limit of one class - Upper limit of previous class}}{2}

= 652=12\dfrac{6 - 5}{2} = \dfrac{1}{2} = 0.5.

Subtract the adjustment factor (0.5) from all the lower limits and add the adjustment factor (0.5) to all the upper limits.

Continuous frequency distribution table :

Class-intervalClass markFrequency
0.5 - 5.535
5.5 - 10.588
10.5 - 15.51312
15.5 - 20.5187
20.5 - 25.5234

Steps to draw frequency polygon :

  1. Take 2 cm along x-axis = 5 units.

  2. Take 2 cm along y-axis = 2 units.

  3. Find the mid-point of class intervals.

  4. A kink is drawn near x-axis to show that the scale begins at 0.5.

  5. Find points corresponding to given frequencies of classes and the mid-points of class-intervals, and plot them.

  6. Join consecutive points by line segments.

  7. Join first end point with mid-point of class -5.5 - 0.5 with zero frequency and join the other end with mid-point of class 25.5 - 30.5 with zero frequency.

The required frequency polygon is shown below:

Join first end point with mid-point of class -5.5 - 0.5 with zero frequency and join the other end with mid-point of class 25.5 - 30.5 with zero frequency. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9.
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