log 27log 9=\dfrac{\log \space 27}{\log \space 9} =log 9log 27=
32\dfrac{3}{2}23
23\dfrac{2}{3}32
3
2
1 Like
Given,
⇒log 27log 9⇒log 33log 32⇒3log 32log 3⇒32.\Rightarrow \dfrac{\log \space 27}{\log \space 9} \\[1em] \Rightarrow \dfrac{\log \space 3^3}{\log \space 3^2} \\[1em] \Rightarrow \dfrac{3\log \space 3}{2\log \space 3} \\[1em] \Rightarrow \dfrac{3}{2}.⇒log 9log 27⇒log 32log 33⇒2log 33log 3⇒23.
Hence, option 1 is the correct option.
Answered By
If log5 (8x - 3) = 3, then x =
8
16
32
40
log9 27 =
13\dfrac{1}{3}31
If logx 0.0016 = 4, then the value of x is:
0.2
0.1
4
If log10 2 = 0.3, then log10 8 =
0.9
0.6
1.2
none of these
