If log_x 243 = 5, then x =

1. 5

2. 3

3. $\dfrac{1}{3}$

4. 1

If log₅ (8x - 3) = 3, then x =

1. 8

2. 16

3. 32

4. 40

$\dfrac{\log \space 27}{\log \space 9} =$

1. $\dfrac{3}{2}$

2. $\dfrac{2}{3}$

3. 3

4. 2

If log_x 0.0016 = 4, then the value of x is:

1. 2

2. 0.2

3. 0.1

4. 4