Factorise : 2ab^2c - 2a + 3b^3c - 3b - 4b^2c^2 + 4c

2ab 2 c \- 2a \+ 3b 3 c \- 3b \- 4b 2 c 2 \+ 4c = 2a(b 2 c \- 1) \+ 3b(b 2 c \- 1) \- 4c(b 2 c \- 1) = (b 2 c \- 1)(2a \+ 3b \- 4c) Hence,2ab 2 c \- 2a \+ 3b 3 c \- 3b \- 4b 2 c 2 \+ 4c = (b 2 c \- 1)(2a \+ 3b \- 4c)

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Mathematics

Factorise :
2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c

Factorisation

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Answer

2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c

= 2a(b²c - 1) + 3b(b²c - 1) - 4c(b²c - 1)

= (b²c - 1)(2a + 3b - 4c)

Hence,2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c = (b²c - 1)(2a + 3b - 4c)

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Mathematics

Factorise :
2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c

Factorisation

Answer

Related Questions

Factorise :
2ab² - aby + 2cby - cy²

Factorise :
ax + 2bx + 3cx - 3a - 6b - 9c

(2x + y)² - (2y + x)² is equal to:
3(x + y) (x - y)
2(x - y) (x + y)
2(y - x) (x + y)
(3x + y) (3x - y)

49 - (x + 5)² is equal to:
(54 - x) (54 + x)
(2 - x) (12 + x)
48(x + 5)²
48(x - 5)²

Mathematics

Factorise :2ab2c - 2a + 3b3c - 3b - 4b2c2 + 4c

Factorisation

Answer

Related Questions

Factorise :2ab2 - aby + 2cby - cy2

Factorise :ax + 2bx + 3cx - 3a - 6b - 9c

(2x + y)2 - (2y + x)2 is equal to:3(x + y) (x - y)2(x - y) (x + y)2(y - x) (x + y)(3x + y) (3x - y)

49 - (x + 5)2 is equal to:(54 - x) (54 + x)(2 - x) (12 + x)48(x + 5)248(x - 5)2

Factorise :
2ab²c - 2a + 3b³c - 3b - 4b²c² + 4c

Factorise :
2ab² - aby + 2cby - cy²

Factorise :
ax + 2bx + 3cx - 3a - 6b - 9c

(2x + y)² - (2y + x)² is equal to:
3(x + y) (x - y)
2(x - y) (x + y)
2(y - x) (x + y)
(3x + y) (3x - y)

49 - (x + 5)² is equal to:
(54 - x) (54 + x)
(2 - x) (12 + x)
48(x + 5)²
48(x - 5)²