Mathematics
Factorise :
ax + 2bx + 3cx - 3a - 6b - 9c
Factorisation
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Answer
ax + 2bx + 3cx - 3a - 6b - 9c
= x(a + 2b + 3c) - 3(a + 2b + 3c)
= (a + 2b + 3c)(x - 3)
Hence,ax + 2bx + 3cx - 3a - 6b - 9c = (a + 2b + 3c)(x - 3)
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Factorise :
ax + 2bx + 3cx - 3a - 6b - 9c
6 Likes
ax + 2bx + 3cx - 3a - 6b - 9c
= x(a + 2b + 3c) - 3(a + 2b + 3c)
= (a + 2b + 3c)(x - 3)
Hence,ax + 2bx + 3cx - 3a - 6b - 9c = (a + 2b + 3c)(x - 3)
Answered By
5 Likes