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Chemistry

40 cm3 of methane (CH4) is reacted with 60 cm3 of oxygen. The equation for the reaction is given below:

CH4 + 2O2 ⟶ CO2 + 2H2O

All volumes are measured at room temperature. What is the total volume of the gases remaining at the end of the reaction?

  1. 60 cm3
  2. 40 cm3
  3. 45 cm3
  4. 50 cm3

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Answer

40 cm3

Reason — From the equation :

CH4 + 2O2 ⟶ CO2 + 2H2O

1 volume of CH4 reacts with 2 volumes of O2

For 40 cm3 of CH4 the required O2 is 40 cm3 x 2 = 80 cm3

Since only 60 cm3 of O2 is available.

The amount of CH4 that reacts with 60 cm3 of O2 is = 602\dfrac{60}{2} = 30 cm3

∴ The excess CH4 remaining is 40 cm3 - 30 cm3 = 10 cm3

From the balanced equation, 2 volumes of O2 produce 1 volume of CO2.

∴ The volume of CO2 produced from 60 cm of O2 is 602\dfrac{60}{2} = 30 cm3

The remaining gases are excess CH4 and produced CO2.

∴ Total volume = 10 cm3 (excess CH4) + 30 cm3 (CO2) = 40 cm3

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