In equation $y = 3 + \dfrac{4x}{5}$, the independent variable is :

1. y

2. x

3. $\dfrac{4x}{5}$

4. $3 + \dfrac{4x}{5}$

If (2x - 1, y + 5) = (3, 10), the values of x and y are :

1. x = 4, y = 5

2. x = 8, y = 5

3. x = 2, y = 5

4. x = 1, y = 5

Abscissa of a point is the solution of equation 3x - 2 = 7 and its ordinate is the solution of equation 8 - 3y = 2. The point is :

1. (3, 2)

2. (-3, 2)

3. (3, -2)

4. (-3, -4)

For each equation given below; name the dependent and independent variables.

(i) $y = \dfrac{4}{3}x - 7$

(ii) x = 9y + 4

(iii) $x = \dfrac{5y + 3}{2}$

(iv) $y = \dfrac{1}{7}(6x + 5)$