5 - x(6 - x) in the form of factors is :
(1 - x)(5 + x)
(1 + x)(5 + x)
(1 - x)(5 - x)
(1 + x)(5 - x)
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Given,
5 - x(6 - x)
= 5 - 6x + x2
= x2 - 6x + 5
= x2 - 5x - x + 5
= x(x - 5) - 1(x - 5)
= (x - 1)(x - 5)
= [-(1 - x).-(5 - x)]
= (1 - x)(5 - x).
Hence, Option 3 is the correct option.
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6x2 - 2 - 4x in the form of factors is :
2(x - 1)(3x - 1)
2(x - 1)(3x + 1)
(2x - 1)(3x - 1)
(6x - 2)(x + 1)
x(x - 1) - 20 in the form of factors is :
(x - 5)(x + 4)
(x - 5)(x - 4)
(x + 5)(x - 4)
(x + 5)(x + 4)
Factorise :
1 - 2a - 3a2
24a3 + 37a2 - 5a