Mathematics
Factorise :
1 - 2a - 3a2
Factorisation
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Answer
Given,
1 - 2a - 3a2
= -(3a2 + 2a - 1)
= -[3a2 + 3a - a - 1]
= -[3a(a + 1) - 1(a + 1)]
= -(3a - 1)(a + 1)
= (1 - 3a)(a + 1).
Hence, 1 - 2a - 3a2 = (1 - 3a)(a + 1).
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