Mathematics
Factorise :
3 - a(4 + 7a)
Factorisation
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Answer
Given,
3 - a(4 + 7a)
= 3 - 4a - 7a2
= -7a2 - 4a + 3
= -(7a2 + 4a - 3)
= -[7a2 + 7a - 3a - 3]
= -[7a(a + 1) - 3(a + 1)]
= -[(a + 1)(7a - 3)]
= -[-(a + 1)(3 - 7a)]
= (a + 1)(3 - 7a).
Hence, 3 - a(4 + 7a) = (a + 1)(3 - 7a).
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