Mathematics
8a3 + 1 in the form of factors is :
(2a + 1)(4a2 - 2a + 1)
(2a - 1)(4a2 - 2a + 1)
(2a + 1)(4a2 + 2a + 1)
(2a - 1)(4a2 + 2a + 1)
Factorisation
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Answer
Given,
8a3 + 1
= (2a)3 + (1)3
= (2a + 1)[(2a)2 - 2a × 1 + (1)2]
= (2a + 1)(4a2 - 2a + 1)
Hence, Option 1 is the correct option.
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