Mathematics
Factorise :
64 - a3b3
Factorisation
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Answer
Given,
64 - a3b3
= (4)3 - (ab)3
= (4 - ab)[(4)2 + 4 × ab + (ab)2]
= (4 - ab)(16 + 4ab + a2b2).
Hence, 64 - a3b3 = (4 - ab)(16 + 4ab + a2b2).
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Factorise :
64 - a3b3
19 Likes
Given,
64 - a3b3
= (4)3 - (ab)3
= (4 - ab)[(4)2 + 4 × ab + (ab)2]
= (4 - ab)(16 + 4ab + a2b2).
Hence, 64 - a3b3 = (4 - ab)(16 + 4ab + a2b2).
Answered By
11 Likes