Factorise : a 6 + 27b 3

Given, a 6 + 27b 3 = (a 2 ) 3 + (3b) 3 = (a 2 + 3b)[(a 2 ) 2 - a 2 × 3b + (3b) 2 ] = (a 2 + 3b)(a 4 - 3a 2 b + 9b 2 ). Hence, a 6 + 27b 3 = (a 2 + 3b)(a 4 - 3a 2 b + 9b 2 ).

Mathematics

Factorise :
a⁶ + 27b³

Factorisation

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Answer

Given,

a⁶ + 27b³

= (a²)³ + (3b)³

= (a² + 3b)[(a²)² - a² × 3b + (3b)²]

= (a² + 3b)(a⁴ - 3a²b + 9b²).

Hence, a⁶ + 27b³ = (a² + 3b)(a⁴ - 3a²b + 9b²).

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Mathematics

Factorise :a6 + 27b3

Factorisation

Answer

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