Mathematics
Factorise :
(a + 2b)2 - a2
Factorisation
11 Likes
Answer
(a + 2b)2 - a2
Using the formula
[∵ (x2 - y2) = (x + y)(x - y)]
= ((a + 2b) + a)((a + 2b) - a)
= (a + 2b + a)(a + 2b - a)
= (a + a + 2b)(a - a + 2b)
= (2a + 2b)(2b)
= 2(a + b)2b
= 4b(a + b)
Hence,(a + 2b)2 - a2 = 4b(a + b)
Answered By
7 Likes
Related Questions
x2 + y2 - 2xy - 1 is equal to :
(x + y - 1) (x - y - 1)
(x + y + 1) (x - y - 1)
(x + y + 1) (x - y + 1)
(x - y + 1) (x - y - 1)
a2 + 2a + 1 - b2 - x2 + 2bx is equal to :
(a + 1 - b + x) (a - 1 - b + x)
(a + 1 + b - x) (a + 1 - b + x)
(a - 1 + b - x) (a - 1 - b + x)
(a - 1 + bx) (a + 1 - bx)
Factorise :
(5a - 3b)2 - 16b2
Factorise :
a4 - (a2 - 3b2)2