Mathematics
x2 + y2 - 2xy - 1 is equal to :
(x + y - 1) (x - y - 1)
(x + y + 1) (x - y - 1)
(x + y + 1) (x - y + 1)
(x - y + 1) (x - y - 1)
Factorisation
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Answer
x2 - y2 - 2xy - 1
Using the formula
[∵ (x - y)2 = x2- 2xy + y2 ]
= (x2 + y2 - 2xy) - 1
= (x - y)2 - 12
Using the formula
[∵ (x2 + y2) = (x + y)(x - y)]
= ((x - y) + (1))((x - y) - (1))
= (x - y + 1)(x - y - 1)
Hence, option 4 is the correct option.
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a2 - 2ab + b2 + a - b is equal to :
(a - b) (a + b - 1)
(a - b) (a + b + 1)
(a + b) (a - b - 1)
(a - b) (a - b + 1)
a2 + 2a + 1 - b2 - x2 + 2bx is equal to :
(a + 1 - b + x) (a - 1 - b + x)
(a + 1 + b - x) (a + 1 - b + x)
(a - 1 + b - x) (a - 1 - b + x)
(a - 1 + bx) (a + 1 - bx)
Factorise :
(a + 2b)2 - a2