Mathematics
a2 - 2ab + b2 + a - b is equal to :
(a - b) (a + b - 1)
(a - b) (a + b + 1)
(a + b) (a - b - 1)
(a - b) (a - b + 1)
Factorisation
10 Likes
Answer
a2 - 2ab + b2 + a - b
Using the formula
[∵ (x - y)2 = x2- 2xy + y2 ]
= (a2 - 2ab + b2) + a - b
= (a - b)2 + 1(a - b)
= (a - b)((a - b) + 1)
= (a - b)(a - b + 1)
Hence, option 4 is the correct option.
Answered By
8 Likes
Related Questions
(2x + y)2 - (2y + x)2 is equal to:
3(x + y) (x - y)
2(x - y) (x + y)
2(y - x) (x + y)
(3x + y) (3x - y)
49 - (x + 5)2 is equal to:
(54 - x) (54 + x)
(2 - x) (12 + x)
48(x + 5)2
48(x - 5)2
x2 + y2 - 2xy - 1 is equal to :
(x + y - 1) (x - y - 1)
(x + y + 1) (x - y - 1)
(x + y + 1) (x - y + 1)
(x - y + 1) (x - y - 1)
a2 + 2a + 1 - b2 - x2 + 2bx is equal to :
(a + 1 - b + x) (a - 1 - b + x)
(a + 1 + b - x) (a + 1 - b + x)
(a - 1 + b - x) (a - 1 - b + x)
(a - 1 + bx) (a + 1 - bx)