(a + b)3 - a - b
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Given,
= (a + b)3 - (a + b)
= (a + b)[(a + b)2 - 1]
= (a + b)[(a + b)2 - 12]
= (a + b)(a + b + 1)(a + b - 1).
Hence, (a + b)3 - a - b = (a + b)(a + b + 1)(a + b - 1).
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Factorise :
4a2b - 9b3
9(a - 2)2 - 16(a + 2)2
a(a - 1) - b(b - 1)
4a2 - (4b2 + 4bc + c2)