Physics

A bulb draws current 1.5 A at 6.0 V. Find the resistance of filament of bulb while glowing.

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Given,

I = 1.5 A

Potential difference = 6 V

R = ?

From Ohm's Law,

V = IR

Substituting the values in the formula, we get,

$6 = 1.5 \times R \\[0.5em] \Rightarrow R = \dfrac{6}{1.5} \\[0.5em] \Rightarrow R = 4Ω$

Hence, the resistance of filament of bulb while glowing = 4Ω

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