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Mathematics

A dice is tossed once. What is the probability of the number 7, coming up ?

Probability

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Answer

Total number of possible outcomes = 6 (i.e., 1, 2, 3, 4, 5, 6)

Number of favourable outcomes (Getting the number 7) = 0

P(Getting the number 7) = Number of favourable outcomesTotal number of possible outcomes\dfrac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}

= 06\dfrac{0}{6}

= 0

Hence, the probability of getting the number 7 is 0.

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