Numbers 1 to 10 written on ten separate identical slips (one number on one slip) are kept in box and mixed well. One slip is chosen at random from the box without looking into it. What is the probability of :

(i) getting a number less than 6 ?

(ii) getting a single digit number ?

(i) Total number of possible outcomes = 10

Number of favourable outcomes (Getting a number less than 6) = 5 (1, 2, 3, 4, 5)

P(Getting a number less than 6) = $\dfrac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}$

= $\dfrac{5}{10}$

= $\dfrac{1}{2}$

Hence, the probability of getting a number less than 6 is $\dfrac{1}{2}$.

(ii) Total number of possible outcomes = 10

Number of favourable outcomes (Getting a single digit number) = 9 (1, 2, 3, 4, 5, 6, 7, 8, 9)

P(Getting a single digit number) = $\dfrac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}$

= $\dfrac{9}{10}$

Hence, the probability of getting a single digit number is $\dfrac{9}{10}$.