Find the probability that a leap year will have 53 Tuesdays.

In a leap year, there are 366 days.

366 days = 52 weeks + 2 days

These 2 days can be (Mon, Tue), (Tue, Wed), (Wed, Thu), (Thu, Fri), (Fri, Sat), (Sat, Sun), and (Sun, Mon).

Total number of possible outcomes = 7

Number of favourable outcomes (Getting Tuesday as one of the extra days) = 2 (i.e., (Mon, Tue), (Tue, Wed)).

P(Getting Tuesday as one of the extra days) = $\dfrac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}$

= $\dfrac{2}{7}$

Hence, the probability that a leap year will have 53 Tuesdays is $\dfrac{2}{7}$.