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Chemistry

A given mass of a gas occupies 143 cm3 at 27°C and 700 mm Hg pressure. What will be its volume at 300 K and 280 mm Hg pressure?

Gas Laws

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Answer

Initial conditionsFinal conditions
P1 = Initial pressure of the gas = 700 mm HgP2 = Final pressure of the gas = 280 mm Hg
V1 = Initial volume of the gas = 143 cm3V2 = Final volume of the gas = ?
T1 = Initial temperature of the gas = 27°C = 27 + 273 = 300 KT2 = Final temperature of the gas = 300 K

By Gas Law:

P1×V1T1=P2×V2T2\dfrac{\text{P}1\times\text{V}1}{\text{T}1} = \dfrac{\text{P}2\times\text{V}2}{\text{T}2}

Substituting the values :

700×143300=280×V2300V2=700×143280V2=357.5 cm3\dfrac{700 \times 143}{300} = \dfrac{280\times\text{\text{V}}2}{300} \\[1em] \text{V}2 =\dfrac{700 \times 143 }{280} \\[1em] \text{V}_2 = 357.5 \text{ cm}^3

∴ Final volume of the gas = 357.5 cm3

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