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Chemistry

88 cm3 of nitrogen is at a pressure of 770 mm mercury. If the pressure is raised to 880 mm Hg, find by how much the volume will diminish, temperature remains constant.

Gas Laws

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Answer

V1 = 88 cm3

P1 = 770 mm

P2 = 880 mm Hg

V2 = ?

By Boyle's Law:

P1V1=P2V2\text{P}1 \text{V}1 = \text{P}2 \text{V}2

Substituting the values :

770×88=880×V2V2=770×88880V2=77770 \times 88 = 880 \times \text{V}2 \\[0.5em] \text{V}2 = \dfrac{770 \times 88}{880} \\[0.5em] \text{V}_2 = 77

V2 = 77 cm3

∴ Decrease in volume = 88 - 77 = 11 cm3

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