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Chemistry

A steel cylinder of internal volume 20 litres is filled with hydrogen at 29 atmospheric pressure. If hydrogen is used to fill a balloon at 1.25 atmospheric pressure at the same temperature, what volume will the gas occupy ?

Gas Laws

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Answer

V1 = 20 litres

P1 = 29 atmospheric pressure

P2 = 1.25 atmospheric pressure

V2 = ?

By Boyle's Law:

P1V1=P2V2\text{P}1 \text{V}1 = \text{P}2 \text{V}2

Substituting the values :

20×29=1.25×V2V2=20×291.25V2=464 litres20 \times 29 = 1.25 \times \text{V}2 \\[0.5em] \text{V}2 = \dfrac{20\times 29}{1.25} \\[0.5em] \text{V}_2 = 464 \text{ litres}

∴ Volume occupied = 464 litres.

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