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Mathematics

A man invests ₹ 5600 at 14% per annum compound interest for 2 years. Calculate :

(i) the interest for the first year.

(ii) the amount at the end of the first year.

(iii) the interest for the second year, correct to the nearest rupee.

Compound Interest

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Answer

(i) For first year :

P = ₹ 5600

R = 14%

T = 1 year

I = P×R×T100=5600×14×1100\dfrac{P \times R \times T}{100} = \dfrac{5600 \times 14 \times 1}{100} = ₹ 784

Hence, interest for the first year = ₹ 784.

(ii) Amount after first year = Principal for first year + Interest

= ₹ 5600 + ₹ 784 = ₹ 6384.

Hence, amount at the end of first year = ₹ 6384.

(iii) For second year :

P = ₹ 5600 + ₹ 784 = ₹ 6384

R = 14%

T = 1 year

I = P×R×T100=6384×14×1100\dfrac{P \times R \times T}{100} = \dfrac{6384 \times 14 \times 1}{100} = ₹ 893.76

Hence, interest for the second year = ₹ 894.

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