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Mathematics

A man saves ₹ 3000 every year and invests it at the end of the year at 10% compound interest. Calculate the total amount of his savings at the end of the third year.

Compound Interest

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Answer

Savings at the end of every year = ₹ 3000

For 2nd year :

P = ₹ 3000

R = 10%

T = 1 year

⇒ I = P×R×T100=3000×10×1100\dfrac{P \times R \times T}{100} = \dfrac{3000 \times 10 \times 1}{100} = ₹ 300

A = ₹ 3000 + ₹ 300 = ₹ 3300

Savings at end of second year = ₹ 3000

For third year :

P = 3000 + 3300 = ₹ 6300

R = 10%

T = 1 year

⇒ I = P×R×T100=6300×10×1100\dfrac{P \times R \times T}{100} = \dfrac{6300 \times 10 \times 1}{100} = ₹ 630

A = ₹ 6300 + ₹ 630 = ₹ 6930

Savings at end of second year = ₹ 3000

Amount at the end of 3rd year

A = ₹ 6930 + ₹ 3000 = ₹ 9930.

Hence, amount at the end of third year = ₹ 9930.

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