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Physics

A stone of mass 500 g is thrown vertically upwards with a velocity of 15ms-1.

Calculate:

(a) the potential energy at the greatest height,

(b) the kinetic energy on reaching the ground

(c) the total energy at its half waypoint.

Work, Energy & Power

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Answer

Mass = 500g

Velocity = 15ms-1

(a) We know,

Potential energy at maximum height = initial kinetic energy

mgh = 12\dfrac{1}{2} mv2

Substituting the values in the equation we get,

KE=12×0.500×152KE=12×0.500×225=56.25JKE = \dfrac{1}{2} \times 0.500 \times 15^2 \\[0.5em] KE = \dfrac{1}{2} \times 0.500\times 225 \\[0.5em] = 56.25J

∴ Potential energy at maximum height = Initial kinetic energy = 56.25J

(b) As we know that,

Kinetic energy on reaching the ground = potential energy at the greatest height

= 56.25J

(c) Total energy at its halfway point = 12\dfrac{1}{2} (K + U) = 56.25J

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