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Chemistry

A vessel of capacity 600 cm3 contains hydrogen gas at a pressure of 330 cm Hg. What will be the pressure of hydrogen gas, when the vessel is connected to another vessel of 300 cm3 capacity ?

Gas Laws

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Answer

V1 = Initial volume of the gas = 600 cm3
P1 = Initial pressure of the gas = 330 cm Hg
V2 = Final volume = 600 + 300 = 900 cm3
P2 = Final pressure of the gas = ?

By Boyle's Law:

P1V1=P2V2\text{P}1 \text{V}1 = \text{P}2 \text{V}2

Substituting the values :

330×600=P2×900P2=600×330900P2=220 cm of Hg330 \times 600 = \text{P}2 \times 900 \\[0.5em] \text{P}2 = \dfrac{600 \times 330 }{900} \\[0.5em] \text{P}_2 = 220 \text{ cm of Hg}

∴ Final pressure = 220 cm of Hg

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