Chemistry

(a) Write the equation in the ionic form

CuSO4 (aq) + Fe (s) ⟶ FeSO4 (aq) + Cu (s)

(b) Divide the above equation into oxidation and reduction half reactions.

Hydrogen

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Answer

(a) The equation in the ionic form:

Cu2+ SO42- + Fe ⟶ Fe2+ SO42- + Cu

(b) Oxidation : Fe ⟶ Fe2+ + 2e-

Reduction : Cu2+ + 2e- ⟶ Cu

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