KnowledgeBoat Logo
|

Mathematics

A(2, 3) and B(–2, 5) are two given points. Find :

(i) the gradient of AB

(ii) the equation of AB

(iii) the co-ordinates of the point, where AB intersects x-axis.

Straight Line Eq

3 Likes

Answer

(i) Given points, A(2, 3) and B(–2, 5)

 Slope of AB =y2y1x2x1=5322=24=12.\Rightarrow \text{ Slope of AB } = \dfrac{y2 - y1}{x2 - x1} \\[1em] = \dfrac{5 - 3}{-2 -2} \\[1em] = \dfrac{2}{-4} = -\dfrac{1}{2}.

Hence, slope = 12-\dfrac{1}{2}.

(ii) By point-slope form,

Equation of the line AB, y - y1 = m(x - x1)

⇒ y - 3 = 12-\dfrac{1}{2}(x - 2)

⇒ 2(y - 3) = -1(x - 2)

⇒ 2y - 6 = -x + 2

⇒ x + 2y = 6 + 2

⇒ x + 2y = 8.

Hence, equation of line is x + 2y = 8.

(iii) The line intersects the x-axis when y = 0. Substituting y = 0 into the equation of the line, x + 2y = 8, we get :

⇒ x + 2(0) = 8

⇒ x = 8

Hence, coordinates of the point where AB intersects the x-axis are (8, 0).

Answered By

3 Likes


Related Questions