If (a² + b² + c²) = 50 and (ab + bc + ca) = 47, find the value of (a + b + c).

Given, (a2 + b2 + c2) = 50 (ab + bc + ca) = 47 Using identity, ⇒ (a + b + c)2 = (a2 + b2 + c2) + 2 (ab + bc + ca) ⇒ (a + b + c)2 = (50) + 2 (47) ⇒ (a + b + c)2 = 50 + 94 ⇒ (a + b + c)2 = 144 ⇒ (a + b + c) = ⇒ (a + b + c) = Hence, (a + b + c) = . Question 34: If (a2 + b2 + c2) = 89 and (ab - bc - ca) = 16, find the value of (a + b - c). Answer Given, (a2 + b2 + c2) = 89 (ab - bc - ca) = 16 Using identity, ⇒ (a + b - c)2 = (a2 + b2 + c2) + 2 (ab - bc - ca) ⇒ (a + b - c)2 = (89) + 2 (16) ⇒ (a + b - c)2 = 89 + 32 ⇒ (a + b - c)2 = 121 ⇒ (a + b - c) = ⇒ (a + b - c) = Hence, (a + b - c) = .

If (a + b + c) = 14 and (a² + b² + c²) = 74, find the value of (ab + bc + ca).

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If (a + b + c) = 15 and (ab + bc + ca) = 74, find the value of (a² + b² + c²).

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If (a² + b² + c²) = 89 and (ab - bc - ca) = 16, find the value of (a + b - c).

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Mathematics

If (a² + b² + c²) = 50 and (ab + bc + ca) = 47, find the value of (a + b + c).

Expansions

Related Questions

If (a + b + c) = 14 and (a² + b² + c²) = 74, find the value of (ab + bc + ca).

If (a + b + c) = 15 and (ab + bc + ca) = 74, find the value of (a² + b² + c²).

If (a² + b² + c²) = 89 and (ab - bc - ca) = 16, find the value of (a + b - c).

Mathematics

If (a2 + b2 + c2) = 50 and (ab + bc + ca) = 47, find the value of (a + b + c).

Expansions

Related Questions

If (a + b + c) = 14 and (a2 + b2 + c2) = 74, find the value of (ab + bc + ca).

If (a + b + c) = 15 and (ab + bc + ca) = 74, find the value of (a2 + b2 + c2).

If (a2 + b2 + c2) = 89 and (ab - bc - ca) = 16, find the value of (a + b - c).

If (a² + b² + c²) = 50 and (ab + bc + ca) = 47, find the value of (a + b + c).

If (a + b + c) = 14 and (a² + b² + c²) = 74, find the value of (ab + bc + ca).

If (a + b + c) = 15 and (ab + bc + ca) = 74, find the value of (a² + b² + c²).

If (a² + b² + c²) = 89 and (ab - bc - ca) = 16, find the value of (a + b - c).