AB = 4.8 cm, BC = 6.8 cm, CD = 5.4 cm, angle B = 60° and AD // BC.
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Steps of construction :
Draw a line segment BC = 6.8 cm.
Draw BX, such that ∠XBC = 60°.
From BX, cut BA = 4.8 cm.
From point A draw QR || BC.
With C as center and radius equal to 5.4 cm draw an arc cutting QR at D.
Join CD and AD.
Hence, ABCD is the required trapezium.
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Area = 24 cm2 and base = 4.8 cm.
Area = 36 cm2 and height = 4.5 cm.
AB = CD = 3.2 cm, BC = 6.0 cm, AD = 4.4 cm and AD // BC.
Its one side = 6 cm and ∠A = 60°.