If tan x° = 5/12, tan y° = 3/4 and AB = 48 m; find the length of CD.

Given: , and AB = 48 m Let BC be `x` m. AC = AB + BC = (48 + x) m. In Δ ADC, And, in Δ BDC, From equation (1), 240 + 5 = 12 CD ⇒ 240 + = 12 CD ⇒ 720 + 20 CD = 36 CD ⇒ 720 = 36 CD - 20 CD ⇒ 16 CD = 720 ⇒ CD = ⇒ CD = 45 Hence, CD = 45 m.