Mathematics
AB and CD are two intersecting lines. Find the position of the point distant 2 cm from AB and 1.8 cm from CD.
Related Questions
ABC is an equilateral triangle of side 3.2 cm. Find the points on AB and AB produced which are 2 cm from BC.
Using ruler and compasses only, construct a ΔABC such that AB = 4.6 cm, BC = 3 cm and ∠ABC = 30°. Complete the rhombus ABDE such that C is equidistant from AB and BD. Locate the point Q on BC such that Q is equidistant from A and B.
Using ruler and compasses only, construct a rhombus ABCD whose diagonals AC and BD are 8 cm and 6 cm long respectively. Find by construction a point P equidistant from AB and AD and also equidistant from C and D. Measure PC.
Using ruler and compasses only, construct a ΔABC in which AB = 4 cm, BC = 5 cm and ∠ABC = 120°.
(i) Locate the point P such that ∠BAP = 90° and BP = CP.
(ii) Measure the length of BP.