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AB is diameter of the circle and ∠ACD = 38°.

AB is diameter of the circle and ∠ACD = 38°. Concise Mathematics Solutions ICSE Class 10.

Assertion (A) : x = 38°.

Reason (R) : ∠ACB = 90°, x = ∠DCB = 90° - 38° = 52°.

AB is diameter of the circle and ∠ACD = 38°. Concise Mathematics Solutions ICSE Class 10.
  1. A is true, R is false.

  2. A is false, R is true.

  3. Both A and R are true and R is correct reason for A.

  4. Both A and R are true and R is incorrect reason for A.

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Answer

AB is diameter of the circle and ∠ACD = 38°. Concise Mathematics Solutions ICSE Class 10.

Join DB and CB.

It is given AB is diameter of the circle and angles in a semicircle is a right angle.

⇒ ∠ACB = 90°

⇒ ∠ACD + ∠DCB = 90°

⇒ 38° + ∠DCB = 90°

⇒ ∠DCB = 90° - 38°

⇒ ∠DCB = 52°

We know that, angles subtended by the same chord in the same segment of a circle are equal.

⇒ ∠BAD (x) = ∠BCD = 52°

So, assertion (A) is false but reason (R) is true.

Hence, option 2 is the correct option.

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