ΔABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. ΔDEF ∼ ΔABC. If EF = 4 cm, then the perimeter of ΔDEF is :
7.5 cm
15 cm
22.5 cm
30 cm

Question

ΔABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. ΔDEF ΔABC. If EF = 4 cm, then the perimeter of ΔDEF is : 1. 7.5 cm 2. 15 cm 3. 22.5 cm 4. 30 cm

KnowledgeBoat · Accepted Answer

Given, ΔDEF ΔABC Perimeter of ΔABC = AB + BC + CA = 3 + 2 + 2.5 = 7.5 cm Since the two triangles are similar, we can write: Hence, option 2 is the correct option.

Mathematics

ΔABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. ΔDEF ∼ ΔABC. If EF = 4 cm, then the perimeter of ΔDEF is :
7.5 cm
15 cm
22.5 cm
30 cm

Similarity

Related Questions

In ΔABC, DE is drawn parallel to BC cutting the other two sides at D and E. If AB = 3.6 cm, AC = 2.4 cm and AD = 2.1 cm, then AE is equal to:
1.05 cm
1.2 cm
1.4 cm
1.8 cm

In the given figure, ∠BAP = ∠DCP = 70°, PC = 6 cm and CA = 4 cm, then PD : DB is equal to:
5 : 3
3 : 5
3 : 2
2 : 3

Mathematics

ΔABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. ΔDEF ∼ ΔABC. If EF = 4 cm, then the perimeter of ΔDEF is :7.5 cm15 cm22.5 cm30 cm

Similarity

Related Questions

In ΔABC, DE is drawn parallel to BC cutting the other two sides at D and E. If AB = 3.6 cm, AC = 2.4 cm and AD = 2.1 cm, then AE is equal to:1.05 cm1.2 cm1.4 cm1.8 cm

In the given figure, ∠BAP = ∠DCP = 70°, PC = 6 cm and CA = 4 cm, then PD : DB is equal to:5 : 33 : 53 : 22 : 3

ΔABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. ΔDEF ∼ ΔABC. If EF = 4 cm, then the perimeter of ΔDEF is :
7.5 cm
15 cm
22.5 cm
30 cm

In ΔABC, DE is drawn parallel to BC cutting the other two sides at D and E. If AB = 3.6 cm, AC = 2.4 cm and AD = 2.1 cm, then AE is equal to:
1.05 cm
1.2 cm
1.4 cm
1.8 cm

In the given figure, ∠BAP = ∠DCP = 70°, PC = 6 cm and CA = 4 cm, then PD : DB is equal to:
5 : 3
3 : 5
3 : 2
2 : 3