In a △ABC, BC = AC and ∠B = 64°, find ∠C.
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In △ABC,
BC = AC
⇒ ∠B = ∠A = 64° [Angles opposite to equal sides are equal]
By angle sum property of a triangle,
⇒ ∠A + ∠B + ∠C = 180°
⇒ 64° + 64° + ∠C = 180°
⇒ 128° + ∠C = 180°
⇒ ∠C = 180° - 128°
⇒ ∠C = 52°.
Hence, ∠C = 52°.
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