In Δ ABC and Δ DEF, AB = 3 x DF, BC = 3 x DE and AC = 3 x EF. Show that the given triangle are similar. Name the two similar triangle on a proper way.

Given, AB = 3 x DF, BC = 3 x DE and AC = 3 x EF

$\Rightarrow \dfrac{\text{AB}}{\text{DF}} = 3, \dfrac{\text{BC}}{\text{DE}} = 3 \text{ and } \dfrac{\text{AC}}{\text{EF}} = 3\\[1em] \Rightarrow \dfrac{\text{AB}}{\text{DF}} = \dfrac{\text{BC}}{\text{DE}} = \dfrac{\text{AC}}{\text{EF}}$

∴ Δ ABC ∼ Δ FDE (By SSS postulates)

Hence, Δ ABC ∼ Δ FDE by SSS.