Mathematics
ABCD is a trapezium and P and Q are the mid-points of the diagonals of AC and BD. Then PQ is equal to : 1. AB 2. CD 3. (AB − CD) 4. (AB + CD)
Related Questions
If bisectors of ∠A and ∠B of a parallelogram ABCD intersect each other at P, of ∠B and ∠C at Q, of ∠C and ∠D at R and of ∠D and ∠A at S, then PQRS is a :
rectangle
rhombus
parallelogram
quadrilateral whose opposite angles are supplementary
Diagonals of a quadrilateral ABCD bisect each other. If ∠A = 35°, then ∠B is equal to :
145°
135°
155°
35°
The diagonals of a quadrilateral intersect at right angles and it has exactly one axis of symmetry. The quadrilateral is a :
square
rhombus
kite
none of these
You have been given following specification regarding a quadrilateral. Measure of all the four angles and the length of one side is given. Would you be able to construct a unique quadrilateral in this case? Justify your answer.