KnowledgeBoat Logo
|

Mathematics

Aditya has a bag containing some black and some white balls. The probability of a randomly chosen ball from this bag being white is (25)\Big(\dfrac{2}{5}\Big). If 5 white balls are added and 5 black balls are removed from the bag, the probability of choosing a white ball changes to (35)\Big(\dfrac{3}{5}\Big). The total number of balls in the bag is:

  1. 10

  2. 25

  3. 45

  4. 50

Probability

1 Like

Answer

Let W be the initial number of white balls and B be the initial number of black balls. The total number of balls,

T = W + B

Given,

The probability of picking a white ball is 25\dfrac{2}{5}.

P(E)=Number of favorable outcomesTotal number of outcomesWT=255W=2T\therefore P(E) = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \\[1em] \Rightarrow \dfrac{W}{T} = \dfrac{2}{5} \\[1em] \Rightarrow 5W = 2T

Since 5 white balls are added and 5 black balls are removed,

The total number of balls remain same and number of white balls increase W + 5.

Given,

The new probability choosing a white ball is 35\dfrac{3}{5}.

P(E)=Number of favorable outcomesTotal number of outcomesW+5T=355(W+5)=3T5W+25=3T(2T)+25=3T25=3T2TT=25.\therefore P(E) = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \\[1em] \Rightarrow \dfrac{W + 5}{T} = \dfrac{3}{5} \\[1em] \Rightarrow 5(W + 5) = 3T \\[1em] \Rightarrow 5W + 25 = 3T \\[1em] \Rightarrow (2T) + 25 = 3T \\[1em] \Rightarrow 25 = 3T - 2T \\[1em] \Rightarrow T = 25.

Hence, option 2 is the correct option.

Answered By

1 Like


Related Questions