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In the adjoining figure, ABCD is a cyclic quadrilateral. If ∠BAD = (2x + 5)° and ∠BCD = (x + 10)°, then x is equal to

In the adjoining figure, ABCD is a cyclic quadrilateral. If ∠BAD = (2x + 5)° and ∠BCD = (x + 10)°, then x is equal to. Circles, ML Aggarwal Understanding Mathematics Solutions ICSE Class 10.
  1. 65

  2. 45

  3. 55

  4. 50

Circles

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Answer

Since, ABCD is a cyclic quadrilateral.

We know that,

The sum of opposite angles of a cyclic quadrilateral is 180°.

⇒ ∠BAD + ∠BCD = 180°

⇒ (2x + 5)° + (x + 10)° = 180°

⇒ 3x° + 15° = 180°

⇒ 3x° = 180° - 15°

⇒ 3x° = 165°

⇒ x° = 165°3\dfrac{165°}{3}

⇒ x° = 55°

⇒ x = 55.

Hence, Option 3 is the correct option.

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