Mathematics
In the adjoining figure, ABCD is a parallelogram. Any line through A cuts DC at a point P and BC produced at Q. Prove that : ar (ΔBPC) = ar (ΔDPQ).
Related Questions
In the adjoining figure, CE is drawn parallel to DB to meet AB produced at E. Prove that : ar (quad. ABCD) = ar (ΔDAE).
In the adjoining figure, ABCD is a parallelogram. AB is produced to a point P and DP intersects BC at Q. Prove that : ar (ΔAPD) = ar (quad. BPCD).
In the adjoining figure, ABCD is a parallelogram. P is a point on BC such that BP : PC = 1 : 2. DP produced meets AB produced at Q. Given ar (ΔCPQ) = 20 cm2. Calculate :
(i) ar (ΔCDP)
(ii) ar (∥ gm ABCD)
In the adjoining figure, ABCD is a parallelogram. P is a point on DC such that ar (ΔAPD) = 25 cm2 and ar (ΔBPC) = 15 cm2. Calculate :
(i) ar (∥ gm ABCD)
(ii) DP : PC
