Mathematics
In the adjoining figure, ABCD is a parallelogram. P and Q are any two points on the sides AB and BC respectively. Prove that :
ar (ΔCPD) = ar (ΔAQD).
Theorems on Area
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Answer
∆CPD and ||gm ABCD are on the same base CD and between the same parallel lines AB and CD.
Area of ∆CPD = Area of ||gm ABCD ……(1)
∆AQD and ||gm ABCD are on the same base AD and between the same parallel lines AD and BC.
Area of ∆AQD = Area of ||gm ABCD ……(2)
From equations (1) and (2), we get :
Area of ∆CPD = Area of ∆AQD.
Hence, proved that area of ∆CPD = area of ∆AQD.
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