Mathematics
In the adjoining figure, ∠ADE = ∠ABC, AE = 8 cm, EB = 7 cm, BC = 9 cm, AD = 10 cm and DC = 2 cm. Then the length of DE is:
6 cm
6.75 cm
7.8 cm
13.5 cm
Related Questions
In the given figure, ∠BAP = ∠DCP = 70°, PC = 6 cm and CA = 4 cm, then PD : DB is equal to:
5 : 3
3 : 5
3 : 2
2 : 3
In the adjoining figure, DE ∥ BC. If AD : DB = 3 : 1 and EA = 3.3 cm, then AC equals:
1.1 cm
4 cm
4.4 cm
5.5 cm
In ΔABC, it is given that AB = 9 cm, BC = 6 cm and CA = 7.5 cm. Also ΔDEF is given such that EF = 8 cm and ΔDEF ∼ ΔABC. Then the perimeter of ΔDEF is:
22.5 cm
25 cm
27 cm
30 cm
In a ΔABC, AB = 10 cm, AC = 14 cm and BC = 6 cm. If AD is the internal bisector of ∠A, then CD is equal to:
3.5 cm
4.8 cm
7 cm
10.5 cm
