Mathematics

In the adjoining figure, find the area of the path (shown shaded) which is 2 m wide all around.

In the adjoining figure, find the area of the path (shown shaded) which is 2 m wide all around. Perimeter & Area Mensuration, ML Aggarwal Understanding Mathematics Solutions ICSE Class 6.

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Answer

Given:

Length of the outer rectangle = 100 m

Breadth of the outer rectangle = 60 m

Width of the path = 2 m

Area of the outer rectangle = length × breadth

= 100 × 60 sq. m

= 6000 sq. m

Length of the inner rectangle = 100 - (2 + 2) = 96 m

Breadth of the inner rectangle = 60 - (2 + 2) = 56 m

Area of the inner rectangle = 96 × 56 sq. m

= 5376 sq. m

Area of the path = Area of outer rectangle - Area of inner rectangle

= 6000 - 5376

= 624 sq. m

Hence, the area of the path is 624 sq. m.

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