An exhibition tent is in the form of a cylinder surmounted by a cone. The height of the tent above the ground is 85 m and the height of the cylindrical part is 50 m. If the diameter of the base is 168 m, find the quantity of canvas required to make the tent. Allow 20% extra for folds and stitching. Give your answers to the nearest m².
Mensuration
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Question

An exhibition tent is in the form of a cylinder surmounted by a cone. The height of the tent above the ground is 85 m and the height of the cylindrical part is 50 m. If the diameter of the base is 168 m, find the quantity of canvas required to make the tent. Allow 20% extra for folds and stitching. Give your answers to the nearest m².

Mensuration

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KnowledgeBoat · Accepted Answer

Total height of the tent = 85 m. Height of the cylindrical part (h₁) = 50 m. From figure, Height of cone (h₂) = 85 - 50 = 35 m. Diameter of the base, d = 168 m. Radius of the base of cylindrical part, r = m. Slant height of the cone, l = . l = m. Surface area of tent (S) = Curved surface area of cylinder + Curved surface area of cone Putting values we get, Adding 20% for folds and stitches, Area of canvas = 50424 + 20% of 50424 Hence, the quantity of canvas required to make the tent is 60509 m².

Mathematics

Mensuration

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