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An object of mass 100 kg is accelerated uniformly from a velocity of 5 ms-1 to 8 ms-1 in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object.

Laws of Motion

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Answer

Given,

Mass of the object (m) = 100 kg

Initial velocity (u) = 5 ms-1

Final velocity (v) = 8 ms-1

Time period (t) = 6 s

Now, initial momentum (m × u) = 100 × 5 = 500 kgms-1

Final momentum (m × v) = 100 × 8 = 800 kgms-1

Hence, Initial momentum = 500 kgms-1 and final momentum = 800 kgms-1

As per the first equation of motion,

a = v - ut\dfrac{\text{v - u}}{\text{t}}

Substituting we get,

a = 856\dfrac{8-5}{6} = 0.5 ms-2

We know, Force = mass x acceleration

Substituting we get,

F = 100 x 0.5 = 50 N

Hence, magnitude of the force = 50 N

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