The areas of two similar triangles are 48 cm² and 75 cm² respectively. If the altitude of the first triangle is 3.6 cm, find the corresponding altitude of the other.
Similarity
2 Likes

Question

The areas of two similar triangles are 48 cm2 and 75 cm2 respectively. If the altitude of the first triangle is 3.6 cm, find the corresponding altitude of the other.

KnowledgeBoat · Accepted Answer

Let the length of altitude of other triangle be x cm We know that, the ratio of the areas of two similar triangles is equal to the ratio of the square of their corresponding altitudes. Hence, the length of altitude of other triangle = 4.5 cm.

Mathematics

The areas of two similar triangles are 48 cm² and 75 cm² respectively. If the altitude of the first triangle is 3.6 cm, find the corresponding altitude of the other.

Similarity

Related Questions

Given that ΔABC ∼ ΔPQR.
(i) If ar(ΔABC) = 49 cm² and ar(ΔPQR) = 25 cm² and AB = 5.6 cm, find the length of PQ.
(ii) If ar(ΔABC) = 28 cm² and ar(ΔPQR) = 63 cm² and PR = 8.4 cm, find the length of AC.
(iii) If BC = 4 cm, QR = 5 cm and ar(ΔABC) = 32 cm² determine ar(ΔPQR).

In the given figure, AB ⟂ BC and DE ⟂ BC. If AB = 9 cm, DE = 3 cm and AC = 24 cm, calculate AD.

In the given figure, DE || BC. If DE = 4 cm, BC = 6 cm and ar(ΔADE) = 20 cm², find the area of ΔABC.